Script-Fu Get Layer Name

[u/FrnchTstFTW]

At this point, I'm begging someone to explain it to me like I'm 5. I just want to get the names of 'drawable' layers passed to my procedure in a set of one or more.

I'm using a 'screen' method with a layer group of layers that contain a unique radial color gradient with local subtle variance and a sort of mask layer below to cast the individual color layers on. I'm using this to generate different colored assets for my neon glow themed game.

This is Gimp 3. My script starts with the 'script-fu-export-layer-variants' procedure in the middle of the text editor. The procedure takes the open image and its selected layers, prompts for a target folder and filename extension, and parses through the selected layers passing them to the 'script-fu-show-export-hide-layer' procedure above. The helper procedure shows the layer, exports the image using the target directory with a file name that concatenates the layer name with the originally provided filename and .png extensions, and hides the layer again to carry on. It's my (probably flawed) understanding that chararray is a representation of a string, but I get an error telling me it's not a string, and the only solution I've found that more specifically gets a name of a drawable has been deprecated and points back to this procedure. The script works as intended short of layers' names being added to the filename causing them all to overwrite the same file.

I'm exhausted from hours of parsing through nearly non-existent/outdated documentation for a little dozen-line automation script. I have no further direction other than pushing through deeper pages of Google hoping not to get pranked by 15 year old forum posts. Please tell me what I stupidly overlooked so a whole day's work isn't wasted.

[u/-pixelmixer-]

Hi,

To get the layer name, just the string:

(car (gimp-item-get-name layer))  

Script-Fu tends to return values wrapped in a list, thats why the error is saying its not a string. The 'car' takes the first item of the list and returns that, which is a string.

for example:

> (gimp-item-get-name 9)
("blue")
> (car (gimp-item-get-name 9))
"blue"

Here are some up to date examples: https://script-fu.github.io/funky/
Lists: https://script-fu.github.io/funky/hub/fundamentals/folder/data-structures/lists/

[u/ofnuts]

My condolences, but well, you picked script-fu 😈(*)

It is however not very difficult to run the thing in the script-fu console and see what is returned by the (gimp-item-get-name layer) and adapt your code to suit.

(*) in Python this is layer.get_name(). Somewhat cozier, ins't it?